Wiki source code of 4 Common function of VB

Last modified by Theodore Xu on 2025/02/27 09:58

version	line-number	content
36.1	1	= Parameters uploading and downloading =
	2
37.1	3	(% class="box infomessage" %)
	4	(((
	5	✎Note:
	6	1.Parameter uploading and downloading is only supported between the same models.
	7	2.F7.11 shows the software version of the inverter, the parameters may differ between different versions, especially between 2.072 and versions below 2.072.
	8	)))
36.1	9
	10	1.Press MF.K and ↑ and wait while the keyboard displays "u~-~-~-~-", the keyboard is uploading the parameters.
	11
	12	2.Remove the keyboard and install to other VB. Please be careful to align the pins when unplugging and plugging in the keyboard.
	13
	14	3.Press MF.K and ↓ and wait while the keyboard display"d~-~-~-~-", the keyboard is downloading the parameters.
	15
1.1	16	= Start up =
	17
	18	~1. Keyboard start and stop, panel potentiometer speed regulation. (F5.17 adjusts the change amplitude of the panel potentiometer)
	19
	20	F0.01=0
	21
	22	F0.03=1
	23
	24	2. The switch starts and stops, and the external voltage potentiometer is used for speed regulation. (AI1: 0-10V input; AI2: 0-20mA/0-10V, realized by AI2 jumper cap)
	25
	26	F0.01=1
	27
	28	F0.03=2
	29
	30	3. The switch starts and stops, the panel up and down keys adjust the speed, and the remote terminal switch is required to control the speed up and down. (Set terminal UP and terminal DOWN in the multi-function terminal). (Control frequency in two places)
	31
	32	F0.01=1
	33
	34	F0.03=1
	35
	36	F5.02=6
	37
	38	F5.03=7
	39
	40	4. Switch start and stop, two switches, when operating the normally open button of one switch, lightly jog, the inverter starts; when operating a normally closed button of the other switch, lightly jog, the inverter stops , Use the three-wire system function.
	41
	42	F0.01=1
	43
	44	F0.03=1
	45
	46	F5.02=3
	47
	48	F5.16=2
	49
	50	5. Two places to control the speed. The inverter on one device needs two positions to control the frequency (speed). Speed (the main and auxiliary frequency sources are used for speed regulation).
	51
	52	F0.03=1
	53
	54	F0.04=2
	55
	56	F0.07=01
	57
17.1	58	6. On some equipment, two potentiometers are required to adjust the speed, one potentiometer 0-10V controls 20HZ, and the other potentiometer controls 0-10V control 25HZ so that the spindle frequency is superimposed, and the frequency is 45HZ.
1.1	59
	60	F0.03=2
	61
	62	F0.04=3 (AI2 jumper is voltage input)
	63
	64	F0.07=01
	65
	66	F5.21=40
	67
	68	F5.25=50
	69
	70	7. The customer needs a fixed speed operation. If it needs to run at 30Hz, there is no need to adjust any place to change the speed. After stopping and then turning on, the operating frequency is still running at 30HZ. How to set the parameters?
	71
	72	F0.03=0
	73
	74	F0.08=30
	75
	76	8. The customer requires the terminal to start. After a power failure, the terminal must be triggered again to start. How to set the parameters?
	77
	78	F0.01=1
	79
	80	F8.18=1
	81
	82	= Acceleration time =
	83
17.1	84	~1. When the device is started, the customer feels that the startup time is too long or the startup time is too short, which parameters need to be modified? (This parameter should be fine-tuned appropriately according to the equipment load. Improper setting can easily cause fault alarms such as overcurrent).
1.1	85
	86	F0.18 (appropriate setting) etc.
	87
	88	= Deceleration time =
	89
	90	~1. After the equipment is started, the customer feels that the deceleration (stopping) time is too long, which parameters need to be modified? (This parameter needs to be fine-tuned according to the equipment load. Improper setting may easily cause fault alarms such as overcurrent).
	91
	92	F0.19 (appropriate setting), etc.
	93
	94	= Stop DC braking =
	95
	96	~1. The inverter is used on a CNC lathe, and the customer needs to stop quickly, that is, brake, which parameters should be set to make the motor stop quickly? (stop DC braking function)
	97
	98	F1.10=0 (must decelerate to stop)
	99
	100	F1.11 Appropriate setting
	101
	102	F1.12 Appropriate setting
	103
	104	F1.13 Appropriate setting
	105
	106	F1.14 Appropriate setting
	107
	108	= Torque boost =
	109
	110	~1. When the inverter is started, the customer reported that the inverter is driving the motor load at low frequencies and is weak at low frequencies, and the torque needs to be increased. Which parameter should be set appropriately?
	111
	112	F4.01 (set appropriately) or change to vector control
	113
	114	= Carrier frequency =
	115
	116	~1. Customers report that there are noises such as harsh screams when the motor is running, or the temperature of the running motor is too high, or when the communication function encounters interference, the function parameter needs to be adjusted to improve the effect.
	117
	118	F0.16 (appropriate setting)
	119
	120	= Upper limit frequency =
	121
	122	1.50HZ operation can not meet the needs of customer equipment, the customer needs to adjust the frequency to 100Hz, what parameters need to be set at this time?
	123
	124	F0.10=100
	125
	126	F0.12=100
	127
	128	= Lower limit frequency =
	129
	130	~1. The user needs the inverter to stop after decelerating to 5HZ, which parameter should be set?
	131
	132	F0.14=5
	133
	134	F0.15=1
	135
	136	= Restore factory value =
	137
	138	~1. The customer reports that the parameters are messed up, how to restore the factory value?
	139
	140	F0.20=1
	141
	142	= Fault clearing =
	143
	144	~1. The fault record can only be recorded 15 times in total. Now the customer needs to clear the fault record, how to set it? Which parameter can make the inverter fault record automatically reset, how many times at most?
	145
	146	F0.20=2
	147
	148	FA.08=5
	149
	150	FE.01=15
	151
	152	= Starting frequency =
	153
	154	~1. The customer needs the inverter to start running at 5HZ, how to set it?
	155
	156	F1.03=5
	157
	158	= PLC operation =
	159
	160	~1. The simple PLC automatic operation function is used on the equipment, the first stage speed is forward rotation, the forward rotation needs 15HZ, and the operation is 5S, the first stage speed is reverse rotation, the reverse rotation requires 20HZ, and the operation is 10S, and now the customer needs to rotate forward and stop. After 10S, it starts to run in the reverse direction. After 10S after the reverse stop, it starts to run forward again, and the cycle is repeated. Which parameter should be set? (Control the acceleration and deceleration time)
	161
	162	F0.03=7
	163
	164	FD.00=30
	165
	166	FD.01=0
	167
	168	FD.02=-40
	169
	170	FD.03=0
	171
	172	FD.18=5
	173
	174	FD.20=10
	175
	176	FD.22=10
	177
	178	FD.24=10
	179
	180	(Or call F8.12 forward and reverse dead time)
	181
	182	= Jump frequency =
	183
	184	~1. In order to avoid the resonance point (vibration point) of the negative cutting of the machine when the inverter is driving the load, which function is needed, and how to set the parameters appropriately for this function? At 10HZ, the vibration range is 2HZ. (Hop frequency)
	185
	186	F8.09=10
	187
	188	F8.11=2
	189
	190	= Jog frequency =
	191
	192	~1. According to customer equipment requirements, a normally open button is needed to give the inverter a jog speed. How do you set the function that needs to be used? And the jog function also requires that the jog frequency acceleration and deceleration time be shortened, so set that parameter The jog frequency is 10Hz, and the acceleration and deceleration time is 5s.
	193
	194	F8.00=10
	195
	196	F8.01=5
	197
	198	F8.02=5
	199
	200	= Multi-speed =
	201
	202	~1. According to the different equipment speed, the customer needs 4 speed stages, the first stage is 40HZ, the second stage is 25HZ, the third stage speed is 10HZ, the fourth stage speed is 50HZ, usually the keyboard potentiometer speed control, how To set which parameters and wiring to meet customer needs.
	203
	204	F0.03=6
	205
	206	F5.02=12
	207
	208	F5.03=13
	209
	210	F5.04=14
	211
	212	F5.05=15
	213
	214	FD.01=80
	215
	216	FD.02=50
	217
	218	FD.04=20
	219
	220	FD.08=100
	221
	222	FD.51=6
	223
	224	F0.04=1(0)
	225
	226	Up to 16 speeds can be achieved, please refer to page 78 of the manual for details.
	227
	228	= Free stop =
	229
	230	1.On some equipment, the equipment does not require deceleration to stop, but the motor stops slowly with the load inertia when it is stopped. For example, when the fan is stopped, the fan needs to be stopped by the load. Which parameter should be set?
	231
	232	F1.10=1
	233
	234	= Reversal is prohibited =
	235
	236	~1. On some devices, customers do not need the motor to reverse, and they are also worried that during the forward rotation, some operators may improperly operate or press the reverse key on the wrong keyboard, which will cause the inverter to reverse and affect the normal operation of the equipment. Now the customer needs us to give him a parameter to prohibit the motor from reversing, which parameter should be set?
	237
	238	F8.13=2
	239
	240	2. The motor originally rotates forward, but when the customer connects the phase sequence UVW of the motor wire, it is difficult to confirm. When the inverter is started, the motor reverses. Now the customer does not need to change the phase sequence UVW of the motor wire. If there is a parameter that can be directly set , Let the motor normally change to forward rotation.
	241
	242	F0.09=1
	243
	244	= Analog output function =
	245
	246	~1. The customer needs to install an ammeter on the power distribution cabinet to display the output current. The wiring is AO1 and GND. In the corresponding function of the parameter group, which parameter should be set? The ammeter can display the output current.
	247
	248	F6.12=2
	249
	250	2. The customer connects a 0-10V tachometer, and finds that the motor speed display is a bit wrong. For example, when running at 50Hz, the speed displayed on the tachometer cannot reach it. How to adjust?
	251
	252	You can measure the output voltage between AO1 and GND and adjust the value of F6.15 and F6.16
	253
	254	= Digital input function =
	255
	256	~1. Since an external switch is needed on the device to control the emergency stop of the motor, which function parameter should be set?
	257
	258	F5.02=10
	259	2. The customer needs to set forward jog and reverse jog functions on the inverter, how to set and wire it?
	260
	261	F5.02=4
	262
	263	F5.03=5
	264	3. When the inverter fails, an external switch is needed to operate the reset function when the inverter fails. How to set and wire?
	265	F5.02=9
	266	4. The inverter terminals control forward and reverse running. Which function parameter should be selected in the multi-function digital input terminal?
	267
	268	F0.01=1
	269
	270	F5.00=1
	271
	272	F5.01=2
	273	5.How to set the remote control frequency if the customer needs an external button?
	274
	275	F5.02=6
	276
	277	F5.03=7
	278
	279	= Digital output function =
	280
	281	~1. The customer needs to use the FM open-collector output function. When the inverter fails, output a switch value to make the fault alarm lamp/fault buzzer act, so that the on-site operator knows that the inverter has a fault alarm and what to do Setup and wiring?
	282
	283	F6.00=1
	284
	285	F6.01=2
	286
	287	2. When the inverter runs more than 20HZ, the relay T1A and T1C terminals output a switch value to control an indicator light, so that the indicator line is connected and the indicator light is on. How to set up and wire?
	288
	289	F6.02=41
	290
	291	F6.28=0
	292
	293	F6.29=11
	294
	295	F6.21=2000
	296	3. When AI1 input is required to be greater than 3.00V and less than 6.00V, relay 1 is closed, how to set the parameters?
	297
	298	F6.02=41
	299
	300	F6.28=9
	301
	302	F6.29=13
	303
	304	F6.31=300
	305
	306	F6.32=600
	307
	308	4.The customer requires relay 1 to act when rotating forward or reverse, how to set it?
	309
	310	F6.02=1
	311
3.1	312	= Motor parameter setting and self-learning =
1.1	313
	314	~1. Familiar with the motor self-learning function.
	315	Need to input the motor parameters F2.01, F2.02, F2.03, F2.04, F2.05 to adjust the value of F2.11 to 1 (premise F0.01=0) or 2, press ENT first, Press RUN again, the self-learning is completed when the panel returns to the monitoring interface. (Necessary operation when changing to vector control)
	316
	317	= Display monitoring =
	318
	319	~1. Master the functions of F7.03, F7.04, and F7.05, all of which are used for display and monitoring. Please refer to page 35 of the manual for details
	320
	321	= Operating mode selection =
	322
	323	~1. Master the definition of each control mode of the F0.00 parameter group.
	324
	325	Vector control, V/F control
	326
	327	= Analog signal gain =
	328
	329	~1. The user uses the AI1 terminal function, and the device is given a voltage of 0-5V for speed regulation. Which parameter should be modified accordingly?
	330
	331	F0.03=2
	332
	333	F5.20=5
	334
	335	2. The user uses the AI2 terminal function, and the device is given a 4-10MA (for example) current speed control, which parameter should be modified accordingly?
	336
	337	F0.03=3
	338
	339	F5.23=2
	340
4.1	341	= Parameter protection =
1.1	342
	343	~1. The protection parameters cannot be modified and the parameters are locked.
	344
	345	F0.21=1
	346
	347	2. The user needs to set a password to prevent some operators from adjusting parameters randomly. Which parameter should be set?
	348
	349	FE.00 = non-zero number
	350
5.1	351	= Set running time action =
1.1	352
	353	~1. The customer sells the machine to the user, worrying that the customer did not pay on time, set some parameters inside the inverter. After the inverter has been running for 10 hours, the inverter will automatically stop and cannot start. Wait for the user to pay before the machine can run. How to set parameters for such a function?
	354	FE.00=Set password
	355
	356	F8.17=10+F7.09
	357
	358	F8.23=1
	359
	360	= Display monitoring options =
	361
	362	~1. The user requires the inverter to display only the speed during operation, which parameter should be modified?
	363
	364	F7.03=4000
	365
	366	F7.06=Speed fine-tuning coefficient
	367	2. The user requires the inverter to display various states during shutdown. Which parameter can be set?
	368
	369	F7.05
	370
18.1	371	= Constant pressure water supply =
	372
19.1	373	The following example uses a current sensor to simulate a water pressure test, the sensor specification is 4-20mA current signal, the range is 16 bar. use the sensor to connect to the AI2 terminal port of the VB.
	374	Firstly please check the software version of F7.11, F7.11 is software version, if the F7.11 is greater than 2.064, please use A4 parameter group, A4 parameter group is special parameter for constant pressure water supply project.
22.1	375	F0.20=1 Factory data reset
18.1	376	A4.00=1
22.1	377	A4.01=Set pressure
18.1	378	A4.03=Sensor range
	379	A4.04=0
	380
	381	If the value of F7.11 is less than or equal to 2.064, use PID parameter group F9.
22.1	382	F0.20=1 Factory data reset
18.1	383	F0.03=8
38.1	384	F5.23=2 Change AI2 range from 0-20mA to 4-20 mA.
18.1	385	F9.01=Upper limit water pressure
	386	F9.02=1 (AI2)
	387	F9.28=1
23.1	388	F9.29=Target value
18.1	389	F9.31=Lower limit water pressure
19.1	390
	391
21.1	392	In the parameter setting of group F9, 20mA is the maximum value of the transducer with a range of 16bar, and F9.01/F9.29/F9.31 are the setting parameters for the water pressure in the VB in percentage. For example when the inverter is required to keep the pressure at 8bar, modify F9.29=50%. F9.01 is the upper limit of water pressure setting, it is recommended to set F9.29=F9.01,of course you can set F9.01=80%,it needs to be greater than or equal to F9.29. If when the control effect of the inverter is slow or the descent time is too long, try reducing the integration time: F9.06 = 0.5 or 1.0.
18.1	393
1.1	394	= PID function =
	395
15.1	396	(% style="text-align:center" %)
16.1	397	[[image:生产流程图.png]]
1.1	398
	399	~1. To be familiar with the PID function of constant pressure water supply, the feedback signal sources are remote pressure gauges and pressure transmitters. How to wire and which parameters should be set? For example, the maximum range of the remote pressure gauge is 1Mpa, and the current user needs to set the panel 0.45 MPa kg pressure, how to set the pressure?
	400	F0.01=0 (panel start and stop)/1 (terminal start and stop)
	401
	402	F0.03=8
	403
	404	F9.00=0
	405
	406	F9.01=45
	407
	408	F9.02=7
	409
	410	F9.05=80
	411
	412	F9.06=2
	413
	414	F9.07=0
	415
	416	F9.28=1
	417
	418	F9.29=45.5
	419
	420	F9.30=3
	421
	422	F9.31=40
	423
	424	F9.32=0
	425
	426	= Communication function =
	427
	428	~1. Familiar with RS485 communication function, communication address, communication speed, communication format, how to set it? Familiar with the address of communication function?
	429	Please refer to page 129 of the manual
	430
	431	Commonly used address: Setting frequency: 1000H (Premise F0.03=9)
	432
	433	Control operation command address: 2000H (premise F0.01=2)
	434
	435	= Grounding =
	436
	437	~1. Understand the meaning and function of the ground wire and connect it correctly.
	438	The grounding terminal E of the inverter must be well grounded, the grounding resistance should be less than 102, and the grounding wire should be thick and short. Multi-strand copper core wire of 3.5mm2 or more should be used.
	439
7.1	440	= Peripheral lines =
1.1	441
	442	~1. Understand the role of peripheral line equipment:
	443
	444	Open
	445
	446	AC contactor
	447	Input AC reactor
	448	Input side filter
	449
	450	DC reactor
	451
	452	Output AC reactor
	453
	454	Output filter
	455
	456	Braking unit
	457
	458	Braking resistor
	459
31.1	460	= EMC =
1.1	461
33.1	462	The input terminal of the inverter has EMC screw access option.
24.1	463
33.1	464	* EMC Screws Installation Role: Filter out the common mode interference signals on the input side to the ground.
35.1	465	* EMC Screw Removal Function: When the grounding of the whole equipment system is unstable, it is easy for the interference signal to enter the input terminal of the VFD, which leads to the inaccurate operation of the terminal motor, and then it is necessary to remove the EMC screws on the machine in order to solve the influence of external interference.
33.1	466
34.1	467	(% class="box infomessage" %)
	468	(((
	469	Do not remove the EMC unless there are special circumstances.
	470	)))
	471
30.1	472	(% style="text-align:center" %)
	473	[[image:企业微信截图_16890580824807.png\|\|height="394" width="284"]]
	474
	475
	476
29.1	477	= Torque mode control on winding project =
25.1	478
	479	Torque mode can only be vector control, torque control refers to the strength, that in the torque mode F0.03 is the default value, modify F0.03 for other values is invalid.
	480
	481	Debugging ideas:
	482
26.1	483	~1. According to the application requirements of the torque command and the upper limit of the frequency.
25.1	484
	485	2. Set the frequency acceleration/deceleration time F0.18/F0.19 and the torque acceleration/deceleration time F3.14/F3.15, the torque acceleration/deceleration time is less than or equal to the frequency acceleration/deceleration time.
	486
	487	3. Start the motor and observe whether the motor can run or not, if it can't run normally, rotate the motor with external force, if it can be started, it is judged to be necessary to increase the static friction coefficient compensation.
	488
	489	4. After the motor is running, observe the motor running state, if the motor is blocked, check whether it is shaking when it is blocked, if it is shaking, increase F3.07, generally 0.01 amplitude increment.
	490
	491	5. When the torque command F3.10 is lower than the percentage of "no-load current / rated current", the running frequency is about: rated frequency * torque command percentage * rated current / no-load current.
	492
	493	6. Static Friction Compensation Logic: During startup, the torque command 1 = F3.11* F3.24 /100 is passed to the performance; after a maintenance time of F3.25 seconds, it reverts to torque command 2 = F3.11; the switching of torque commands 1 /2 occurs through the torque acceleration and deceleration times F3.14 / F3.15;
	494
	495	7. Auxiliary debugging parameters: filter coefficient F3.07 and static friction compensation F3.24/ F3.25.
	496
26.1	497	F0.00=0 Vector control
25.1	498
27.1	499	F0.18=2.0 Acceleration time
25.1	500
27.1	501	F0.19=2.0 Deceleration time
25.1	502
27.1	503	F2.01=Motor rated power
25.1	504
	505	F2.02=Motor rated voltage
	506
	507	F2.03=Rated motor current
	508
	509	F2.04=Rated motor frequency
	510
	511	F2.05=Rated motor speed
	512
27.1	513	F2.11=1 Static tuning
25.1	514
27.1	515	F3.01=0.2 Speed loop integration time
25.1	516
27.1	517	F3.07=0.005 Speed loop filter coefficient
25.1	518
27.1	519	F3.09=1 Torque control
25.1	520
27.1	521	F3.10=1 Torque control upper limit source
25.1	522
27.1	523	F3.11=200 Torque upper limit setting
25.1	524
27.1	525	F3.12=50 Torque control maximum frequency
25.1	526
27.1	527	F3.14=1.2 Torque control acceleration time
25.1	528
27.1	529	F3.15=1.2 Torque control deceleration time
25.1	530
28.1	531	F3.16=120 Torque stiffness factor
25.1	532
	533	Torque control commissioning instructions:
	534
27.1	535	F0.18: Frequency acceleration time
25.1	536
27.1	537	F0.19: Frequency deceleration time
25.1	538
27.1	539	F3.14: Torque acceleration time
25.1	540
27.1	541	F3.15: Torque deceleration time
25.1	542
27.1	543	F3.07: Frequency low-pass filtering factor
25.1	544
27.1	545	F3.24: Static friction compensation
25.1	546
27.1	547	F3.25: Static friction compensation time

Wiki source code of 4 Common function of VB

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