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Last modified by Theodore Xu on 2025/02/21 14:13
From version 21.1
edited by Theodore Xu
on 2024/03/27 09:37
Change comment: There is no comment for this version
To version 25.1
edited by Theodore Xu
on 2025/02/21 14:13
Change comment: There is no comment for this version

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... ... @@ -54,7 +54,7 @@
54 54  |2|(% colspan="2" %)AI1
55 55  |3|(% colspan="2" %)AI2
56 56  |4|(% colspan="2" %)Reserved
57 -|5|(% colspan="2" %)PULSE setting DI6（Reserved）
57 +|5|(% colspan="2" %)PULSE setting DI6
58 58  |6|(% colspan="2" %)Multi-stage speed setting
59 59  |7|(% colspan="2" %)Simple PLC
60 60  |8|(% colspan="2" %)PID
... ... @@ -257,12 +257,12 @@
257 257  
258 258  Select the running state of the AC drive when the set frequency is lower than the lower limit frequency. In order to prevent the motor from running at low speed for a long time, this function can be used to choose to stop.
259 259  
260 +== Carrier frequency ==
261 +
260 260  (% class="table-bordered" %)
261 261  |(% rowspan="2" style="width:139px" %)** F0.16**|(% style="width:680px" %)Carrier Frequency|(% style="width:429px" %)Default|(% style="width:204px" %)Model Dependent
262 262  |(% style="width:680px" %)Setting Range|(% colspan="2" style="width:633px" %)0.5kHz~~16.0kHz
263 263  
264 -= Carrier frequency =
265 -
266 266  This function adjusts the carrier frequency of the AC drive. By adjusting the carrier frequency, the motor noise can be reduced, the resonance point of the mechanical system can be avoided, the leakage current of the line to the ground and the interference caused by the inverter can be reduced.
267 267  
268 268  When the carrier frequency is low, the higher harmonic components of the output current increase, the motor loss increases, and the motor temperature rise increases.
... ... @@ -1314,9 +1314,8 @@
1314 1314  |11|Count value|0~~Maximum count value
1315 1315  |12|Communication setting|-10000~~10000
1316 1316  |13|Motor Speed|0~~Rotation speed corresponding to maximum output frequency
1317 -|14|Output Current|0-1000A,as 0-10V
1318 - 0-1000V,as 0-10V
1319 -|15|Output Voltage|0.0V~~1000.0V
1317 +|14|Output Current|0-1000A, as 0-10V
1318 +|15|Output Voltage|0-1000V, as 0-10V
1320 1320  
1321 1321  (% class="table-bordered" %)
1322 1322  |(% rowspan="2" %)**F6.14**|FMP output maximum frequency|Default|50.00kHz 　　
... ... @@ -2392,7 +2392,7 @@
2392 2392  
2393 2393  This function means that the inverter will not stop when the power is cut instantaneously. In the case of an instantaneous power failure or a sudden voltage drop, the inverter will reduce its output speed, and compensate for the voltage drop by feeding back energy through the load to keep the inverter running in a short time.
2394 2394  
2395 -If the instantaneous stop non-stop function selection is valid, when the bus voltage is lower than the voltage indicated by the instantaneous stop non-stop action judgment voltage (FA.25), the inverter will decelerate according to the instantaneous stop action selection. When the stop action judgment voltage (FA.25) represents the voltage, and the duration is maintained for the momentary stop and non-stop voltage rise judgment time (FA.24), the inverter resumes the set frequency operation; otherwise the inverter will continue to reduce the operating frequency to Stop at 0 o'clock. Instantaneous stop non-stop function if shown.
2394 +If the instantaneous stop non-stop function selection is valid, when the bus voltage is lower than the voltage indicated by the instantaneous stop non-stop action judgment voltage (FA.25), the inverter will decelerate according to the instantaneous stop action selection. When the bus voltage exceeds FA.23 and the duration is greater than FA.24, the inverter resumes the set frequency operation; otherwise the inverter will continue to reduce the operating frequency to Stop at 0 o'clock. Instantaneous stop non-stop function if shown.
2396 2396  
2397 2397  The deceleration time of instantaneous power failure is too long, the load feedback energy is small, and the low voltage can not be effectively compensated; the deceleration time is too short, the load feedback energy is large, which will cause overvoltage protection. Please adjust the deceleration time appropriately according to the load inertia and the weight of the load.
2398 2398